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.64x^2-5x-6000=0
a = .64; b = -5; c = -6000;
Δ = b2-4ac
Δ = -52-4·.64·(-6000)
Δ = 15385
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-\sqrt{15385}}{2*.64}=\frac{5-\sqrt{15385}}{1.28} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+\sqrt{15385}}{2*.64}=\frac{5+\sqrt{15385}}{1.28} $
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